x^2+120x-6280=0

Solution for x^2+120x-6280=0 equation:

x^2+120x-6280=0

a = 1; b = 120; c = -6280;
Δ = b2-4ac
Δ = 1202-4·1·(-6280)
Δ = 39520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{39520}=\sqrt{16*2470}=\sqrt{16}*\sqrt{2470}=4\sqrt{2470}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-4\sqrt{2470}}{2*1}=\frac{-120-4\sqrt{2470}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+4\sqrt{2470}}{2*1}=\frac{-120+4\sqrt{2470}}{2}
$